3u^2-9u+4=0

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Solution for 3u^2-9u+4=0 equation: 



3u^2-9u+4=0

a = 3; b = -9; c = +4;
Δ = b2-4ac
Δ = -92-4·3·4
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{33}}{2*3}=\frac{9-\sqrt{33}}{6}
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{33}}{2*3}=\frac{9+\sqrt{33}}{6}
$

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